So this is probably late but here are the calculations:
-2dB is a voltage ratio of 0.7943 x=10^(-2/20)
This is a simple resistive series divider. Rx=(1-.7943)*10000/.7943
rx= 2589 ohms. Subract the 75 output impedance of your DAC and you get 2514 ohms.
Closest 1% value is 2.49kOhms
Closest 0.1% value is 2.52kOhms
I like Vishay metal film resistors.
Calculating back, the 1% 2.49k resistor will result in an attenuation of 1.98 dB.
You would put this resistor in series with the center conductor of your single ended interconnect, preferably at the preamp input end so the cable capacitance would not have a deleterious effect on frequency response.
There is a caveat to this method. It assumes that the input impedance of your preamp is constant vs. frequency, and this is not always the case.
Enjoy!
Tom