If your speakers have an 8 ohm impedance, then to bring that down to an effective 4 ohm load would require using an 8 ohm resistor in parallel with each speaker. (The formula for parallel resistances is to multiply their resistances and then divide the result by their sum, so for this example: (8 * 8) / (8 + 8) which is 64/16 giving you a net 4 ohm load.) While the amp would then deliver its 4 ohm power rating, half of that would be going through the resistor and not to the speaker. So in addition to taking into consideration whether the amp may sound better driving an 8 or 4 ohm load :S, you would only get 15W of the total 30 available to the speaker.